Friday, February 3, 2012

Can anyone help?how many 3 digets area codes{WITH NO REPEATING DIGETS) ?

CAN BE MADE USING 2,5,7 AND 9?

What is probablity that one of these area code is divisible by 9?Not visible by 2?

Can anyone help?how many 3 digets area codes{WITH NO REPEATING DIGETS) ?
4 x 3 x 2

=24 area codes

There are some properties regarding divisibility of numbers by 9 and 2. I don't remember what they are.

Out of these 24 numbers, you'll have to find how many are divisible by 9 and not by 2.

Just wait for more answers.

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